What is the critical f(x)=2-3x^2 ?

The critical f(x)=2-3x^2 is x=0

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critical f(x)=2-3x^2

critical points

f (x) = 2 - 3 x^{2}

x = 0

Solution steps

2 - 3 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

2 - 3 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0

f (x) = \frac{10 x - 18}{x ^{2} - 7 x + 10}

(1, 3), (- 1, - 1)

y = - x^{2} - 10 x + 56

f (x) = x^{3} + \frac{3}{2} x^{2} - 6 x + 10

f (x) = 4^{x - 2}