extreme f(x)=-(e^{2x})/(-2x-5)

Lösung

extrempunkte

f (x) = - \frac{e ^{2 x}}{- 2 x - 5}

Minimum (- 2, \frac{1}{e ^{4}})

Schritte zur Lösung

f^{'} (x) = - \frac{- 4 e ^{2 x} x - 8 e ^{2 x}}{( - 2 x - 5 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - \frac{5}{2},

Absteigend

: - \frac{5}{2} < x < - 2,

Ansteigend

: - 2 < x < \infty

Stecke

x = - 2

- \frac{e ^{2 x}}{- 2 x - 5} : \frac{1}{e ^{4}}

Minimum (- 2, \frac{1}{e ^{4}})

e x t re m e f (x) = (10 - 2 x) (10 - 2 x) (x)

e x t re m e f (x) = (x - 1)^{2} (x + 3)^{2}

e x t re m e U (a, b) = aa + bb

e x t re m e f (x) = \frac{1}{3} x^{3} - 7 x^{2} + 24 x + 6

e x t re m e f (x) = (\frac{4860}{x}) + 17 x + 752774