extreme f(x)=(10-2x)(10-2x)(x)

Lösung

extrempunkte

f (x) = (10 - 2 x) (10 - 2 x) (x)

Maximum (\frac{5}{3}, \frac{2000}{27}), Minimum (5, 0)

Schritte zur Lösung

f^{'} (x) = 4 (x - 5) (3 x - 5)

Intervalle finden:

Ansteigend

: - \infty < x < \frac{5}{3},

Absteigend

: \frac{5}{3} < x < 5,

Ansteigend

: 5 < x < \infty

Stecke

x = \frac{5}{3}

(10 - 2 x) (10 - 2 x) x : \frac{2000}{27}

Maximum (\frac{5}{3}, \frac{2000}{27})

Stecke

x = 5

(10 - 2 x) (10 - 2 x) x : 0

Minimum (5, 0)

Maximum (\frac{5}{3}, \frac{2000}{27}), Minimum (5, 0)

e x t re m e f (x) = (x - 1)^{2} (x + 3)^{2}

e x t re m e U (a, b) = aa + bb

e x t re m e f (x) = \frac{1}{3} x^{3} - 7 x^{2} + 24 x + 6

e x t re m e f (x) = (\frac{4860}{x}) + 17 x + 752774

e x t re m e f (x) = x e^{- x^{2} - y^{2}}