extreme f(x)=x+sqrt(8-x)

Lösung

extrempunkte

f (x) = x + 8 - x

Maximum (\frac{31}{4}, \frac{33}{4}), Minimum (8, 8)

Schritte zur Lösung

f^{'} (x) = 1 - \frac{1}{2 8 - x}

Intervalle finden:

Ansteigend

: - \infty < x < \frac{31}{4},

Absteigend

: \frac{31}{4} < x < 8

Stecke

x = \frac{31}{4}

x + 8 - x : \frac{33}{4}

Maximum (\frac{31}{4}, \frac{33}{4})

Stecke

x = 8

x + 8 - x : 8

Minimum (8, 8)

Maximum (\frac{31}{4}, \frac{33}{4}), Minimum (8, 8)

e x t re m e \frac{( x ^{2} - 5 )}{x + 3}

e x t re m e f (x) = 2 x^{2} + 3 x y + 4 y^{2} - 7 x - 11 y

e x t re m e f (x) = \frac{2}{2} x + sin (x)

e x t re m e f (x) = \frac{x}{3 x ^{2} - 1}

e x t re m e f (x) = (x + 2)^{3} (x - 3)