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Popular Functions >

extreme f(x)= 1/(x^2+3)

Solution

extreme

Solution

Maximum (0, \frac{1}{3})

Solution steps

f^{'} (x) = - \frac{2 x}{( x ^{2} + 3 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1}{x ^{2} + 3} : \frac{1}{3}

Maximum (0, \frac{1}{3})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/(x^2+3) ?
The extreme f(x)= 1/(x^2+3) is Maximum(0, 1/3)