What is the extreme f(x)=x^4-8x^3+2 ?

The extreme f(x)=x^4-8x^3+2 is Saddle(0,2),Minimum(6,-430)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=x^4-8x^3+2

extreme

Saddle (0, 2), Minimum (6, - 430)

Solution steps

f^{'} (x) = 4 x^{3} - 24 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 0

into

x^{4} - 8 x^{3} + 2 : 2

Saddle (0, 2)

Plug

x = 6

into

x^{4} - 8 x^{3} + 2 : - 430

Minimum (6, - 430)

Saddle (0, 2), Minimum (6, - 430)

What is the extreme f(x)=x^4-8x^3+2 ?
The extreme f(x)=x^4-8x^3+2 is Saddle(0,2),Minimum(6,-430)