What is the extreme f(x,y)=x^2+y^2-xy-2x+y ?

The extreme f(x,y)=x^2+y^2-xy-2x+y is Minimum(1,0)

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extreme f(x,y)=x^2+y^2-xy-2x+y

extreme

Minimum (1, 0)

Solution steps

Find the critical points:

(1, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(1, 0) :

Minimum

Minimum (1, 0)

What is the extreme f(x,y)=x^2+y^2-xy-2x+y ?
The extreme f(x,y)=x^2+y^2-xy-2x+y is Minimum(1,0)