What is the extreme f(x*y)=3x^2-4xy+3y^2+8x-17y+5 ?

The extreme f(x*y)=3x^2-4xy+3y^2+8x-17y+5 is Minimum(1, 7/2)

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extreme f(x*y)=3x^2-4xy+3y^2+8x-17y+5

extreme

Minimum (1, \frac{7}{2})

Solution steps

Find the critical points:

(1, \frac{7}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 6

D (x, y) = 20

Check the sign of at each critical point

Check critical point

(1, \frac{7}{2}) :

Minimum

Minimum (1, \frac{7}{2})

What is the extreme f(x*y)=3x^2-4xy+3y^2+8x-17y+5 ?
The extreme f(x*y)=3x^2-4xy+3y^2+8x-17y+5 is Minimum(1, 7/2)