What is the inverse of f(x)= 1/3 ((x-4)/2)^2-1 ?

The inverse of f(x)= 1/3 ((x-4)/2)^2-1 is 2sqrt(3x+3)+4,-2sqrt(3x+3)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of f(x)= 1/3 ((x-4)/2)^2-1

inverse

f (x) = \frac{1}{3} (\frac{x - 4}{2})^{2} - 1

2 3 x + 3 + 4, - 2 3 x + 3 + 4

Solution steps

y = \frac{1}{3} (\frac{x - 4}{2})^{2} - 1

Replace

x

with

y

x = \frac{1}{3} (\frac{y - 4}{2})^{2} - 1

Solve for

y, x = \frac{1}{3} (\frac{y - 4}{2})^{2} - 1

2 3 x + 3 + 4, - 2 3 x + 3 + 4

What is the inverse of f(x)= 1/3 ((x-4)/2)^2-1 ?
The inverse of f(x)= 1/3 ((x-4)/2)^2-1 is 2sqrt(3x+3)+4,-2sqrt(3x+3)+4