求反函数 f(x)=1+2*sin(1-2/(x+1))

解答

求反函数

f (x) = 1 + 2 \cdot sin (1 - \frac{2}{x + 1})

\frac{- arcsin ( \frac{x - 1}{2} ) - 1}{arcsin ( \frac{x - 1}{2} ) - 1}

求解步骤

求解

sin (1 - \frac{2}{x + 1}), y = 1 + 2 \cdot sin (1 - \frac{2}{x + 1})

sin (1 - \frac{2}{x + 1}) = \frac{y - 1}{2}

sin (a) = b \Rightarrow a = arcsin (b)

1 - \frac{2}{x + 1} = arcsin (\frac{y - 1}{2})

求解

x, 1 - \frac{2}{x + 1} = arcsin (\frac{y - 1}{2})

\frac{- arcsin ( \frac{y - 1}{2} ) - 1}{arcsin ( \frac{y - 1}{2} ) - 1}

替代

y = x

\frac{- arcsin ( \frac{x - 1}{2} ) - 1}{arcsin ( \frac{x - 1}{2} ) - 1}

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