What is the range of f(x)= 1/(x+8)+3 ?

The range of f(x)= 1/(x+8)+3 is f(x) 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)= 1/(x+8)+3

range

f (x) = \frac{1}{x + 8} + 3

f (x) < 3 or f (x) > 3

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x + 8} + 3

Inverse of

\frac{1}{x + 8} + 3 : \frac{- 8 x + 25}{x - 3}

\frac{- 8 x + 25}{x - 3}

Find the domain of each inverse function

Domain of

\frac{- 8 x + 25}{x - 3} : x < 3 or x > 3

Combine the intervals

f (x) < 3 or f (x) > 3

\frac{8 t}{4 t ^{2} + 8 t}

9 - x

f (x) = x^{4} - 32 x^{2} + 5

y = 10 x + 2, (6, 5)

f (x) = \frac{x - 3}{x ^{2} - 5 x + 6}

What is the range of f(x)= 1/(x+8)+3 ?
The range of f(x)= 1/(x+8)+3 is f(x)<3\lor f(x)>3