What is the inverse of 1/(6x^2+9x-2) ?

The inverse of 1/(6x^2+9x-2) is (-9x+sqrt(129x^2+24x))/(12x),(-9x-sqrt(129x^2+24x))/(12x)

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inverse of 1/(6x^2+9x-2)

inverse

\frac{1}{6 x ^{2} + 9 x - 2}

\frac{- 9 x + 129 x ^{2} + 24 x}{12 x}, \frac{- 9 x - 129 x ^{2} + 24 x}{12 x}

Solution steps

y = \frac{1}{6 x ^{2} + 9 x - 2}

Replace

x

with

y

x = \frac{1}{6 y ^{2} + 9 y - 2}

Solve for

y, x = \frac{1}{6 y ^{2} + 9 y - 2}

\frac{- 9 x + 129 x ^{2} + 24 x}{12 x}, \frac{- 9 x - 129 x ^{2} + 24 x}{12 x}

What is the inverse of 1/(6x^2+9x-2) ?
The inverse of 1/(6x^2+9x-2) is (-9x+sqrt(129x^2+24x))/(12x),(-9x-sqrt(129x^2+24x))/(12x)