What is the inverse of f(x)=7x^2+4,x>= 0 ?

The inverse of f(x)=7x^2+4,x>= 0 is sqrt((x-4)/7),-sqrt((x-4)/7)

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inverse of f(x)=7x^2+4,x>= 0

inverse

f (x) = 7 x^{2} + 4, x \geq 0

\frac{x - 4}{7}, - \frac{x - 4}{7}

Solution steps

y = 7 x^{2} + 4

Replace

x

with

y

x = 7 y^{2} + 4

Solve for

y, x = 7 y^{2} + 4

\frac{x - 4}{7}, - \frac{x - 4}{7}

What is the inverse of f(x)=7x^2+4,x>= 0 ?
The inverse of f(x)=7x^2+4,x>= 0 is sqrt((x-4)/7),-sqrt((x-4)/7)