What is the domain of f(x)=sqrt(3-\sqrt{x^2-16)} ?

The domain of f(x)=sqrt(3-\sqrt{x^2-16)} is -5<= x<=-4\lor 4<= x<= 5

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domain of f(x)=sqrt(3-\sqrt{x^2-16)}

domain

f (x) = 3 - x^{2} - 16

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

Interval Notation

[- 5, - 4] \cup [4, 5]

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

The function domain

- 5 \leq x \leq - 4 or 4 \leq x \leq 5

f (x) = \frac{n + 1}{n ^{2} - 6 n + 8}

\frac{x + 1}{x ^{2} - 5 x + 6}

f (s) = 2 - \frac{3}{s ^{2}}

f (x) = \frac{x ^{2} - 1}{x - 1}

f (x) = 2 x^{2} + 6

What is the domain of f(x)=sqrt(3-\sqrt{x^2-16)} ?
The domain of f(x)=sqrt(3-\sqrt{x^2-16)} is -5<= x<=-4\lor 4<= x<= 5