What is the inverse of f(s)=2-3/(s^2) ?

The inverse of f(s)=2-3/(s^2) is sqrt(-3/(s-2)),-sqrt(-3/(s-2))

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inverse of f(s)=2-3/(s^2)

inverse

f (s) = 2 - \frac{3}{s ^{2}}

- \frac{3}{s - 2}, - - \frac{3}{s - 2}

Solution steps

y = 2 - \frac{3}{s ^{2}}

Replace

s

with

y

s = 2 - \frac{3}{y ^{2}}

Solve for

y, s = 2 - \frac{3}{y ^{2}}

- \frac{3}{s - 2}, - - \frac{3}{s - 2}

f (x) = \frac{x ^{2} - 1}{x - 1}

f (x) = 2 x^{2} + 6

\frac{6 x - 6}{x + 2}

f (x) = \frac{3}{4} x - 5

x + 7

What is the inverse of f(s)=2-3/(s^2) ?
The inverse of f(s)=2-3/(s^2) is sqrt(-3/(s-2)),-sqrt(-3/(s-2))