What is the inverse of 1/(s(s+a)) ?

The inverse of 1/(s(s+a)) is (-as+sqrt(a^2s^2+4s))/(2s),(-as-sqrt(a^2s^2+4s))/(2s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse of 1/(s(s+a))

inverse

\frac{1}{s ( s + a )}

\frac{- a s + a ^{2} s ^{2} + 4 s}{2 s}, \frac{- a s - a ^{2} s ^{2} + 4 s}{2 s}

Solution steps

y = \frac{1}{s ( s + a )}

Replace

s

with

y

s = \frac{1}{y ( y + a )}

Solve for

y, s = \frac{1}{y ( y + a )}

\frac{- a s + a ^{2} s ^{2} + 4 s}{2 s}, \frac{- a s - a ^{2} s ^{2} + 4 s}{2 s}

What is the inverse of 1/(s(s+a)) ?
The inverse of 1/(s(s+a)) is (-as+sqrt(a^2s^2+4s))/(2s),(-as-sqrt(a^2s^2+4s))/(2s)