What is the inverse of f(x)=3x^2-3x-18 ?

The inverse of f(x)=3x^2-3x-18 is (3+sqrt(12x+225))/6 ,(3-sqrt(12x+225))/6

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inverse of f(x)=3x^2-3x-18

inverse

f (x) = 3 x^{2} - 3 x - 18

\frac{3 + 12 x + 225}{6}, \frac{3 - 12 x + 225}{6}

Solution steps

y = 3 x^{2} - 3 x - 18

Replace

x

with

y

x = 3 y^{2} - 3 y - 18

Solve for

y, x = 3 y^{2} - 3 y - 18

\frac{3 + 12 x + 225}{6}, \frac{3 - 12 x + 225}{6}

What is the inverse of f(x)=3x^2-3x-18 ?
The inverse of f(x)=3x^2-3x-18 is (3+sqrt(12x+225))/6 ,(3-sqrt(12x+225))/6