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Popular >

midpoint (7,-1),(-2,10)

Solution

midpoint

(7, - 1), (- 2, 10)

Solution

(\frac{5}{2}, \frac{9}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (7, - 1), (x_{2}, y_{2}) = (- 2, 10)

= (\frac{- 2 + 7}{2}, \frac{10 - 1}{2})

Refine

= (\frac{5}{2}, \frac{9}{2})

Popular Examples

domain of x/(x+3)domain

\frac{x}{x + 3}

inverse of y=9x^2 inverse

y = 9 x^{2}

asymptotes of f(x)=(x+3)/(x^2-9)asymptotes

f (x) = \frac{x + 3}{x ^{2} - 9}

domain of f(x)=\sqrt[4]{x^2-6x}domain

domain of f(x)= x/(sqrt(x-10))domain

f (x) = \frac{x}{x - 10}

Frequently Asked Questions (FAQ)

What is the midpoint (7,-1),(-2,10) ?
The midpoint (7,-1),(-2,10) is (5/2 , 9/2)