What is the domain of f(x)=\sqrt[4]{x^2-6x} ?

The domain of f(x)=\sqrt[4]{x^2-6x} is x = 6

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domain of f(x)=\sqrt[4]{x^2-6x}

domain

x \leq 0 or x \geq 6

Interval Notation

(- \infty, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

The function domain

x \leq 0 or x \geq 6

f (x) = \frac{x}{x - 10}

f (x) = \frac{x + 3}{2}

f (x) = \frac{x ^{2} - 4 x + 6}{x + 4}

\frac{x + 5}{4}

\frac{- 4 - 7 x}{3 x - 1}

What is the domain of f(x)=\sqrt[4]{x^2-6x} ?
The domain of f(x)=\sqrt[4]{x^2-6x} is x<= 0\lor x>= 6