What is the inverse of f(x)=sqrt(25-x^2) ?

The inverse of f(x)=sqrt(25-x^2) is sqrt(-x^2+25),-sqrt(-x^2+25)

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inverse of f(x)=sqrt(25-x^2)

inverse

f (x) = 25 - x^{2}

- x^{2} + 25, - - x^{2} + 25

Solution steps

y = 25 - x^{2}

Replace

x

with

y

x = 25 - y^{2}

Solve for

y, x = 25 - y^{2}

- x^{2} + 25, - - x^{2} + 25

f (x) = \frac{2}{x - 10}

- 49 - x^{2}

f (x) = 4 x^{3} - 48 x - 6

(- 3, - 2), (- 1, - 2)

x - 1 + 1

What is the inverse of f(x)=sqrt(25-x^2) ?
The inverse of f(x)=sqrt(25-x^2) is sqrt(-x^2+25),-sqrt(-x^2+25)