What is the domain of f(x)=sqrt(2/(x-10)) ?

The domain of f(x)=sqrt(2/(x-10)) is x>10

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domain of f(x)=sqrt(2/(x-10))

domain

f (x) = \frac{2}{x - 10}

x > 10

Interval Notation

(10, \infty)

Solution steps

Find non-negative values for radicals:

x > 10

Find undefined (singularity) points:

x = 10

Combine real regions and undefined points for final function domain

x > 10

- 49 - x^{2}

f (x) = 4 x^{3} - 48 x - 6

(- 3, - 2), (- 1, - 2)

x - 1 + 1

f (x) = \frac{x + 2}{x ^{2} + 3 x - 10}

What is the domain of f(x)=sqrt(2/(x-10)) ?
The domain of f(x)=sqrt(2/(x-10)) is x>10