What is the inverse of g(x)= 1/3 (x-5)(x+1) ?

The inverse of g(x)= 1/3 (x-5)(x+1) is (4+sqrt(12x+36))/2 ,(4-sqrt(12x+36))/2

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inverse of g(x)= 1/3 (x-5)(x+1)

inverse

g (x) = \frac{1}{3} (x - 5) (x + 1)

\frac{4 + 12 x + 36}{2}, \frac{4 - 12 x + 36}{2}

Solution steps

y = \frac{1}{3} (x - 5) (x + 1)

Replace

x

with

y

x = \frac{1}{3} (y - 5) (y + 1)

Solve for

y, x = \frac{1}{3} (y - 5) (y + 1)

\frac{4 + 12 x + 36}{2}, \frac{4 - 12 x + 36}{2}

What is the inverse of g(x)= 1/3 (x-5)(x+1) ?
The inverse of g(x)= 1/3 (x-5)(x+1) is (4+sqrt(12x+36))/2 ,(4-sqrt(12x+36))/2