What is the inverse of f(x)= 1/(sqrt(x^2-4)) ?

The inverse of f(x)= 1/(sqrt(x^2-4)) is (sqrt(1+4x^2))/x ,-(sqrt(1+4x^2))/x

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inverse of f(x)= 1/(sqrt(x^2-4))

inverse

f (x) = \frac{1}{x ^{2} - 4}

\frac{1 + 4 x ^{2}}{x}, - \frac{1 + 4 x ^{2}}{x}

Solution steps

y = \frac{1}{x ^{2} - 4}

Replace

x

with

y

x = \frac{1}{y ^{2} - 4}

Solve for

y, x = \frac{1}{y ^{2} - 4}

\frac{1 + 4 x ^{2}}{x}, - \frac{1 + 4 x ^{2}}{x}

What is the inverse of f(x)= 1/(sqrt(x^2-4)) ?
The inverse of f(x)= 1/(sqrt(x^2-4)) is (sqrt(1+4x^2))/x ,-(sqrt(1+4x^2))/x