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Popular Functions >

p(x)= 1/(x^2+1)

Solution

p (x) = \frac{1}{x ^{2} + 1}

Solution

Domain : - \infty < x < \infty

Range : 0 < f (x) \leq 1

Y Intercepts : (0, 1)

Asymptotes : Horizontal y = 0

Extreme Points : Maximum (0, 1)

+1

Interval Notation

Domain : (- \infty, \infty)

Range : (0, 1]

Solution steps

Domain of

\frac{1}{x ^{2} + 1} : - \infty < x < \infty

Range of

\frac{1}{x ^{2} + 1} : 0 < f (x) \leq 1

Axis interception points of

\frac{1}{x ^{2} + 1} :

Y Intercepts

: (0, 1)

Asymptotes of

\frac{1}{x ^{2} + 1} :

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} + 1} :

Maximum

(0, 1)

Graph

Popular Examples

f(m)=m^2-12m+925

inverse of f(x)= 1/2 (x-4)^2+1

inverse of f(x)=(3-2x)/(2x-5)

inverse of f(x)=(x^2)/(1+x^2)

Frequently Asked Questions (FAQ)

What is the p(x)= 1/(x^2+1) ?
The p(x)= 1/(x^2+1) is