What is the inverse of f(x)=(x^2)/(1+x^2) ?

The inverse of f(x)=(x^2)/(1+x^2) is sqrt(-x/(x-1)),-sqrt(-x/(x-1))

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inverse of f(x)=(x^2)/(1+x^2)

inverse

f (x) = \frac{x ^{2}}{1 + x ^{2}}

- \frac{x}{x - 1}, - - \frac{x}{x - 1}

Solution steps

y = \frac{x ^{2}}{1 + x ^{2}}

Replace

x

with

y

x = \frac{y ^{2}}{1 + y ^{2}}

Solve for

y, x = \frac{y ^{2}}{1 + y ^{2}}

- \frac{x}{x - 1}, - - \frac{x}{x - 1}

What is the inverse of f(x)=(x^2)/(1+x^2) ?
The inverse of f(x)=(x^2)/(1+x^2) is sqrt(-x/(x-1)),-sqrt(-x/(x-1))