What is the f(x)=((x+2)(x-4))/((x+4)(x-5)(x+1)) ?

The f(x)=((x+2)(x-4))/((x+4)(x-5)(x+1)) is

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f(x)=((x+2)(x-4))/((x+4)(x-5)(x+1))

f (x) = \frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )}

Domain : x < - 4 or - 4 < x < - 1 or - 1 < x < 5 or x > 5

Range : - \infty < f (x) < \infty

X Intercepts : (- 2, 0), (4, 0), Y Intercepts : (0, \frac{2}{5})

Asymptotes : Vertical x = - 4, x = - 1, x = 5, Horizontal y = 0

Extreme Points : None

Interval Notation

Domain : (- \infty, - 4) \cup (- 4, - 1) \cup (- 1, 5) \cup (5, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )} : x < - 4 or - 4 < x < - 1 or - 1 < x < 5 or x > 5

Range of

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )} : - \infty < f (x) < \infty

Axis interception points of

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )} :

X Intercepts

: (- 2, 0), (4, 0),

Y Intercepts

: (0, \frac{2}{5})

Asymptotes of

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )} :

Vertical

: x = - 4, x = - 1, x = 5,

Horizontal

: y = 0

Extreme Points of

\frac{( x + 2 ) ( x - 4 )}{( x + 4 ) ( x - 5 ) ( x + 1 )} :

None

What is the f(x)=((x+2)(x-4))/((x+4)(x-5)(x+1)) ?
The f(x)=((x+2)(x-4))/((x+4)(x-5)(x+1)) is