What is the extreme f(x)=x^4e^x-3 ?

The extreme f(x)=x^4e^x-3 is Maximum(-4,(256)/(e^4)-3),Minimum(0,-3)

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extreme f(x)=x^4e^x-3

extreme points

f (x) = x^{4} e^{x} - 3

Maximum (- 4, \frac{256}{e ^{4}} - 3), Minimum (0, - 3)

Solution steps

f^{'} (x) = e^{x} x^{4} + 4 e^{x} x^{3}

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 4

into

x^{4} e^{x} - 3 : \frac{256}{e ^{4}} - 3

Maximum (- 4, \frac{256}{e ^{4}} - 3)

Plug

x = 0

into

x^{4} e^{x} - 3 : - 3

Minimum (0, - 3)

Maximum (- 4, \frac{256}{e ^{4}} - 3), Minimum (0, - 3)

f (x) = x + \frac{4}{x}

y = 3 x + 3

f (x) = x^{3} - 4 x^{2} + 3 x

f (x) = (ln (x))^{5}

(- 1, 12), (1, 0)

What is the extreme f(x)=x^4e^x-3 ?
The extreme f(x)=x^4e^x-3 is Maximum(-4,(256)/(e^4)-3),Minimum(0,-3)