What is the domain of f(x)=sqrt(x^3-4x^2+3x) ?

The domain of f(x)=sqrt(x^3-4x^2+3x) is 0 = 3

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domain of f(x)=sqrt(x^3-4x^2+3x)

domain

f (x) = x^{3} - 4 x^{2} + 3 x

0 \leq x \leq 1 or x \geq 3

Interval Notation

[0, 1] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 1 or x \geq 3

The function domain

0 \leq x \leq 1 or x \geq 3

f (x) = (ln (x))^{5}

(- 1, 12), (1, 0)

x^{2} + 5

y = tan (2 x)

f (x) = \frac{x ^{2}}{x ^{2} - 4}

What is the domain of f(x)=sqrt(x^3-4x^2+3x) ?
The domain of f(x)=sqrt(x^3-4x^2+3x) is 0<= x<= 1\lor x>= 3