What is the domain of y=6-sqrt(x+36) ?

The domain of y=6-sqrt(x+36) is x>=-36

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domain of y=6-sqrt(x+36)

domain

y = 6 - x + 36

x \geq - 36

Interval Notation

[- 36, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 36

The function domain

x \geq - 36

2 x (3 x - 8)

[\frac{5}{z - 0.2} - \frac{5}{z + 0.4} - 3]

x^{2} - 6 x + 8

(17, - 17), (0, - 19)

f (x) = (x + 2)^{2} - 4