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midpoint
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inverse of f(x)=(x+2)^2-4intercepts of f(x)=-16x^2+60x+2domain of f(x)=x^5-3x+5inverse of f(x)=6x(1-x)slope ofintercept 2y-x=4
Frequently Asked Questions (FAQ)
What is the midpoint (17,-17),(0,-19) ?
The midpoint (17,-17),(0,-19) is (17/2 ,-18)