What is the tangent of f(x)= 1/2 x^2,\at x=2 ?

The tangent of f(x)= 1/2 x^2,\at x=2 is y=2x-2

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tangent of f(x)= 1/2 x^2,\at x=2

tangent of

f (x) = \frac{1}{2} x^{2}, at x = 2

y = 2 x - 2

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{1}{2} x^{2} : \frac{df ( x )}{d x} = x

Compute the slope of

f (x) = \frac{1}{2} x^{2}

x = 2 : m = 2

Find the line with slope m=

2

and passing through

(2, 2) : y = 2 x - 2

y = 2 x - 2

\int \frac{1 - x ^{2}}{1 - x} d x

\int \frac{t + 1}{3 t ^{2} + 6 t - 5} d t

\frac{\partial}{\partial y} (x e^{w})

x \to 2 - lim (\frac{3 x}{x - 2})

f (x) = (x^{2} + 3 x)^{2}

What is the tangent of f(x)= 1/2 x^2,\at x=2 ?
The tangent of f(x)= 1/2 x^2,\at x=2 is y=2x-2