What is the derivative of f(x)=(x^2+3x)^2 ?

The derivative of f(x)=(x^2+3x)^2 is 2(x^2+3x)(2x+3)

What is the first derivative of f(x)=(x^2+3x)^2 ?

The first derivative of f(x)=(x^2+3x)^2 is 2(x^2+3x)(2x+3)

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derivative of

f (x) = (x^{2} + 3 x)^{2}

2 (x^{2} + 3 x) (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x)^{2})

Apply the chain rule:

2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

= 2 (x^{2} + 3 x) \frac{d}{d x} (x^{2} + 3 x)

\frac{d}{d x} (x^{2} + 3 x) = 2 x + 3

= 2 (x^{2} + 3 x) (2 x + 3)

\int \frac{8}{x ^{2} x ^{2} + 16} d x

x \to \infty lim (81 x^{2} + x - 9 x)

\int 7 e^{9 x} d x

\int y \cdot e^{- y} d y

(2 y + 2 t - 9) d t + (8 y + 2 t - 1) d y = 0

What is the derivative of f(x)=(x^2+3x)^2 ?
The derivative of f(x)=(x^2+3x)^2 is 2(x^2+3x)(2x+3)
What is the first derivative of f(x)=(x^2+3x)^2 ?
The first derivative of f(x)=(x^2+3x)^2 is 2(x^2+3x)(2x+3)