What is the limit as x approaches 1+of 1/(x^2-1) ?

The limit as x approaches 1+of 1/(x^2-1) is infinity

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limit as x approaches 1+of 1/(x^2-1)

x \to 1 + lim (\frac{1}{x ^{2} - 1})

\infty

Solution steps

x \to 1 + lim (\frac{1}{x ^{2} - 1})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{2} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

y^{^{''}} - 4 y = 0, y (0) = 0, y^{^{'}} (0) = 1

f (x) = \frac{4}{1 + x ^{2}}, (1, 2)

\frac{3 s + 4}{s ^{2} + 2}

x \to 0 lim (x^{2} + 3 x - 6)

\frac{5}{2} y^{4} y^{^{'}} - \frac{y ^{5} + 4}{x ^{3}} = 0, y (1) = 0

What is the limit as x approaches 1+of 1/(x^2-1) ?
The limit as x approaches 1+of 1/(x^2-1) is infinity