What is the solution for 5/2 y^4y^'-(sqrt(y^5+4))/(x^3)=0,y(1)=0 ?

The solution for 5/2 y^4y^'-(sqrt(y^5+4))/(x^3)=0,y(1)=0 is y=\sqrt[5]{(9x^4-10x^2+1)/(4x^4)}

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5/2 y^4y^'-(sqrt(y^5+4))/(x^3)=0,y(1)=0

\frac{5}{2} y^{4} y^{^{'}} - \frac{y ^{5} + 4}{x ^{3}} = 0, y (1) = 0

Solution steps

\frac{5}{2} y^{4} y^{'} (x) - \frac{y ^{5} + 4}{x ^{3}} = 0

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What is the solution for 5/2 y^4y^'-(sqrt(y^5+4))/(x^3)=0,y(1)=0 ?
The solution for 5/2 y^4y^'-(sqrt(y^5+4))/(x^3)=0,y(1)=0 is y=\sqrt[5]{(9x^4-10x^2+1)/(4x^4)}