What is the solution for y^'=y(xy^3+4) ?

The solution for y^'=y(xy^3+4) is y=(2\sqrt[3]{6}e^{4x})/(\sqrt[3]{-12e^{12x)x+e^{12x}+c_{1}}}

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y^'=y(xy^3+4)

y^{^{'}} = y (x y^{3} + 4)

Solution steps

y^{'} (x) = y (x y^{3} + 4)

Solve Bernoulli ODE:

\int e^{a t} sin (t) d t

\int sec^{2} (\frac{x}{4}) d x

\int e^{3 t} sin (t) d t

\frac{\partial}{\partial y} (\frac{2 y}{x})

\frac{1}{s ^{3} + 4 s ^{2} + 3 s}

What is the solution for y^'=y(xy^3+4) ?
The solution for y^'=y(xy^3+4) is y=(2\sqrt[3]{6}e^{4x})/(\sqrt[3]{-12e^{12x)x+e^{12x}+c_{1}}}