What is the tangent of f(x)= 4/(1+x^2),(1,2) ?

The tangent of f(x)= 4/(1+x^2),(1,2) is y=-2x+4

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tangent of f(x)= 4/(1+x^2),(1,2)

tangent of

f (x) = \frac{4}{1 + x ^{2}}, (1, 2)

y = - 2 x + 4

Solution steps

Find the slope of

f (x) = \frac{4}{1 + x ^{2}} : \frac{df ( x )}{d x} = - \frac{8 x}{( 1 + x ^{2} ) ^{2}}

Compute the slope of

f (x) = \frac{4}{1 + x ^{2}}

(1, 2) : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 2) : y = - 2 x + 4

y = - 2 x + 4

\frac{3 s + 4}{s ^{2} + 2}

x \to 0 lim (x^{2} + 3 x - 6)

\frac{5}{2} y^{4} y^{^{'}} - \frac{y ^{5} + 4}{x ^{3}} = 0, y (1) = 0

(- 6, - 5), (4, 4)

\frac{d}{d x} (sin (x) csc (x))

What is the tangent of f(x)= 4/(1+x^2),(1,2) ?
The tangent of f(x)= 4/(1+x^2),(1,2) is y=-2x+4