What is the integral of 4/(1+x) ?

The integral of 4/(1+x) is 4ln|1+x|+C

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integral of 4/(1+x)

\int \frac{4}{1 + x} d x

4 ln ∣ 1 + x ∣ + C

Solution steps

\int \frac{4}{1 + x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{1 + x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= 4 \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 4 ln ∣ u ∣

Substitute back

u = 1 + x

= 4 ln ∣ 1 + x ∣

Add a constant to the solution

= 4 ln ∣ 1 + x ∣ + C

\int (2 x - 1) ln (x) d x

\int \frac{2 x ^{2} + x + 15}{x + 3} d x

\int_{1}^{2} 2 - x d x

y^{^{'}} = x y + 3

x \to - \infty lim (2 + e^{x})