What is the limit as x approaches-infinity of 2+e^x ?

The limit as x approaches-infinity of 2+e^x is 2

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limit as x approaches-infinity of 2+e^x

x \to - \infty lim (2 + e^{x})

2

Solution steps

x \to - \infty lim (2 + e^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (2) + x \to - \infty lim (e^{x})

x \to - \infty lim (2) = 2

x \to - \infty lim (e^{x}) = 0

= 2 + 0

Simplify

= 2

\frac{d}{d x} (0.1 x)

y = x^{2} + 2, (2, 6)

\int 1 - r^{2} d r

x^{2}, - x^{2} + 18 x

e^{x} - 8 x^{7}

What is the limit as x approaches-infinity of 2+e^x ?
The limit as x approaches-infinity of 2+e^x is 2