What is the solution for y^'=xsqrt(y+3) ?

The solution for y^'=xsqrt(y+3) is y=(x^4}{16}+\frac{c_{1}x^2+c_{1}^2)/4-3

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y^'=xsqrt(y+3)

y^{^{'}} = x y + 3

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2} + c _{1}^{2}}{4} - 3

Solution steps

y^{'} (x) = x y + 3

Solve separable ODE:

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2} + c _{1}^{2}}{4} - 3

y = \frac{x ^{4}}{16} + \frac{c _{1} x ^{2} + c _{1}^{2}}{4} - 3

x \to - \infty lim (2 + e^{x})

\frac{d}{d x} (0.1 x)

y = x^{2} + 2, (2, 6)

\int 1 - r^{2} d r

x^{2}, - x^{2} + 18 x

What is the solution for y^'=xsqrt(y+3) ?
The solution for y^'=xsqrt(y+3) is y=(x^4}{16}+\frac{c_{1}x^2+c_{1}^2)/4-3