What is the derivative of 8sqrt(x)+6x^{3/4} ?

The derivative of 8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}

What is the first derivative of 8sqrt(x)+6x^{3/4} ?

The first derivative of 8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}

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\frac{d}{d x} (8 x + 6 x^{\frac{3}{4}})

\frac{4}{x ^{\frac{1}{2}}} + \frac{9}{2 x ^{\frac{1}{4}}}

Solution steps

\frac{d}{d x} (8 x + 6 x^{\frac{3}{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (6 x^{\frac{3}{4}})

\frac{d}{d x} (8 x) = \frac{4}{x ^{\frac{1}{2}}}

\frac{d}{d x} (6 x^{\frac{3}{4}}) = \frac{9}{2 x ^{\frac{1}{4}}}

= \frac{4}{x ^{\frac{1}{2}}} + \frac{9}{2 x ^{\frac{1}{4}}}

\int \frac{4}{1 + x} d x

\int (2 x - 1) ln (x) d x

\int \frac{2 x ^{2} + x + 15}{x + 3} d x

\int_{1}^{2} 2 - x d x

y^{^{'}} = x y + 3

What is the derivative of 8sqrt(x)+6x^{3/4} ?
The derivative of 8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}
What is the first derivative of 8sqrt(x)+6x^{3/4} ?
The first derivative of 8sqrt(x)+6x^{3/4} is 4/(x^{1/2)}+9/(2x^{1/4)}