{
"query": {
"display": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(ue^{2x}\\right)$$",
"symbolab_question": "DERIVATIVE#\\frac{\\partial }{\\partial x}(ue^{2x})"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Partial Derivatives",
"default": "\\frac{\\partial }{\\partial x}(u)e^{2x}+e^{2x}\\cdot 2u",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(ue^{2x}\\right)=\\frac{\\partial\\:}{\\partial\\:x}\\left(u\\right)e^{2x}+e^{2x}\\cdot\\:2u$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(ue^{2x}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Product Rule: $$\\left(f{\\cdot}g\\right)'=f'{\\cdot}g+f{\\cdot}g'$$",
"secondary": [
"$$f=u,\\:g=e^{2x}$$"
],
"result": "=\\frac{\\partial\\:}{\\partial\\:x}\\left(u\\right)e^{2x}+\\frac{\\partial\\:}{\\partial\\:x}\\left(e^{2x}\\right)u",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Product%20Rule",
"practiceTopic": "Product Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(e^{2x}\\right)=e^{2x}\\cdot\\:2$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(e^{2x}\\right)",
"steps": [
{
"type": "interim",
"title": "Apply the chain rule:$${\\quad}e^{2x}\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(e^{2x}\\right)",
"result": "=e^{2x}\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the chain rule: $$\\frac{df\\left(u\\right)}{dx}=\\frac{df}{du}\\cdot\\frac{du}{dx}$$",
"secondary": [
"$$f=e^{v},\\:\\:v=2x$$"
],
"result": "=\\frac{\\partial\\:}{\\partial\\:v}\\left(e^{v}\\right)\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Chain%20Rule",
"practiceTopic": "Chain Rule"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:v}\\left(e^{v}\\right)=e^{v}$$",
"input": "\\frac{\\partial\\:}{\\partial\\:v}\\left(e^{v}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{\\partial\\:}{\\partial\\:v}\\left(e^{v}\\right)=e^{v}$$",
"result": "=e^{v}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAm78XQdiccdYNZFUr3qlNRHHI5S0StY1FdtOqqOPr0Te9fpuTWGA/bcx8V9AIGMLhjgq4Lxd6wfEqqn7isBB4lorzea8M9Hp5QtXq9EUDk+3rAS+CcUEgTtci3JLKvUQTBmRFYEhwKyvVrS/hQ+v39LJLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"result": "=e^{v}\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)"
},
{
"type": "step",
"primary": "Substitute back $$v=2x$$",
"result": "=e^{2x}\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)"
}
],
"meta": {
"interimType": "Derivative Chain Rule 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAkUQcsJHLWU6j3MiiASfoRu/M3hESAhJ79Q7OQNfwXSMNgFtoYbJnzv+zNETDbCQXMYYCqvl+e94pW032CAXDQMNZFvGc7UIqQxoEt41Cm4Ep3G/GREkml78tgv19XBlf32Cck6ykF/R4sTjfi2uxUgo3oe/oyhMy2+1TQhDBd2fzGrMGuaCGoCkBTn65ypufhm2/z8V92sLreSsUccmX/A"
}
},
{
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)=2$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(2x\\right)",
"steps": [
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=2\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)"
},
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{\\partial\\:}{\\partial\\:x}\\left(x\\right)=1$$",
"result": "=2\\cdot\\:1"
},
{
"type": "step",
"primary": "Simplify",
"result": "=2",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYp9ApVx6pk97jrrFSzJxOAno4QJ4HBk7oek4Ww/3d//tnFjOV6V4e2DrBKqW1EhFu2EtmEvdU5EIfaZixikaOU0OG38IleojCyebAtZy+3Tm9JiwEB0ZXmaMqMWNNpbCrpbGGfud1pShayFW5kHjQPuwiNrEngO+NNvZ9sqNu+2V"
}
},
{
"type": "step",
"result": "=e^{2x}\\cdot\\:2"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"result": "=\\frac{\\partial\\:}{\\partial\\:x}\\left(u\\right)e^{2x}+e^{2x}\\cdot\\:2u"
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Partial%20Derivatives",
"practiceTopic": "Partial Derivatives"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Apply the Product Rule:
Popular Examples
integral of (-8)/((x-2)(x^2+4))-3y^'+9x^2=0(\partial)/(\partial x)(6y^2sqrt(x))(xsqrt(x))^'(dy)/(dt)+7y=e^{4t},y(0)=10
Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(ue^{2x}) ?
The answer to (\partial)/(\partial x)(ue^{2x}) is (\partial)/(\partial x)(u)e^{2x}+e^{2x}*2u