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Popular >

-3y^'+9x^2=0

Solution

- 3 y^{^{'}} + 9 x^{2} = 0

Solution

y = x^{3} + c_{1}

Solution steps

- 3 y^{'} (x) + 9 x^{2} = 0

Isolate

y^{'} (x) : y^{'} (x) = 3 x^{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 x^{2} d x

\int 3 x^{2} d x = x^{3} + c_{1}

y = x^{3} + c_{1}

Popular Examples

(\partial)/(\partial x)(6y^2sqrt(x))

\frac{\partial}{\partial x} (6 y^{2} x)

(x x)^{^{'}}

(dy)/(dt)+7y=e^{4t},y(0)=10

\frac{d y}{d t} + 7 y = e^{4 t}, y (0) = 10

(\partial)/(\partial x)(e^{-ax^2})

\frac{\partial}{\partial x} (e^{- a x^{2}})

(x+4)^2y^'+3(x+4)y=4

(x + 4)^{2} y^{^{'}} + 3 (x + 4) y = 4

Frequently Asked Questions (FAQ)

What is the solution for -3y^'+9x^2=0 ?
The solution for -3y^'+9x^2=0 is y=x^3+c_{1}