{
"query": {
"display": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(6y^{2}\\sqrt{x}\\right)$$",
"symbolab_question": "DERIVATIVE#\\frac{\\partial }{\\partial x}(6y^{2}\\sqrt{x})"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Derivatives",
"subTopic": "Partial Derivatives",
"default": "\\frac{3y^{2}}{\\sqrt{x}}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\frac{\\partial\\:}{\\partial\\:x}\\left(6y^{2}\\sqrt{x}\\right)=\\frac{3y^{2}}{\\sqrt{x}}$$",
"input": "\\frac{\\partial\\:}{\\partial\\:x}\\left(6y^{2}\\sqrt{x}\\right)",
"steps": [
{
"type": "step",
"primary": "Treat $$y\\:$$as a constant"
},
{
"type": "step",
"primary": "Take the constant out: $$\\left(a{\\cdot}f\\right)'=a{\\cdot}f'$$",
"result": "=6y^{2}\\frac{\\partial\\:}{\\partial\\:x}\\left(\\sqrt{x}\\right)"
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt{a}=a^{\\frac{1}{2}}$$",
"result": "=6y^{2}\\frac{\\partial\\:}{\\partial\\:x}\\left(x^{\\frac{1}{2}}\\right)",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\frac{d}{dx}\\left(x^a\\right)=a{\\cdot}x^{a-1}$$",
"result": "=6y^{2}\\frac{1}{2}x^{\\frac{1}{2}-1}",
"meta": {
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Power%20Rule",
"practiceTopic": "Power Rule"
}
},
{
"type": "interim",
"title": "Simplify $$6y^{2}\\frac{1}{2}x^{\\frac{1}{2}-1}:{\\quad}\\frac{3y^{2}}{\\sqrt{x}}$$",
"input": "6y^{2}\\frac{1}{2}x^{\\frac{1}{2}-1}",
"result": "=\\frac{3y^{2}}{\\sqrt{x}}",
"steps": [
{
"type": "interim",
"title": "$$x^{\\frac{1}{2}-1}=x^{-\\frac{1}{2}}$$",
"input": "x^{\\frac{1}{2}-1}",
"steps": [
{
"type": "interim",
"title": "Join $$\\frac{1}{2}-1:{\\quad}-\\frac{1}{2}$$",
"input": "\\frac{1}{2}-1",
"result": "=x^{-\\frac{1}{2}}",
"steps": [
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:2}{2}$$",
"result": "=-\\frac{1\\cdot\\:2}{2}+\\frac{1}{2}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{-1\\cdot\\:2+1}{2}"
},
{
"type": "interim",
"title": "$$-1\\cdot\\:2+1=-1$$",
"input": "-1\\cdot\\:2+1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=-2+1"
},
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-2+1=-1$$",
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s731snK5z/nd3Sq/6JpCqiX1XTSum/z5kLpMzXS1UJIew02FKSBoQo9V3G05AlnWtTyCE30rzMlUAIVDyhseMBropKGn5MuXZnb2ZCo/hVsBU="
}
},
{
"type": "step",
"result": "=\\frac{-1}{2}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{2}"
}
],
"meta": {
"interimType": "Algebraic Manipulation Join Concise Title 1Eq"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7qijEBDcyPMwV4Y1jeiGyoO0se7vRyav6BwUCJZptwG3MwViaLUXkeD+JukROhWdjQYCY06ctBCI/puUxKEtzAQH2kDe5DGYTz3TrPquGdIjtHZXPNLHlLyai31n5HH4G6M8osviUPEkWv33aMbZrSFQW3Chm7McvYpuS87Y5EFs="
}
},
{
"type": "step",
"result": "=6\\cdot\\:\\frac{1}{2}y^{2}x^{-\\frac{1}{2}}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-b}=\\frac{1}{a^b}$$",
"secondary": [
"$$x^{-\\frac{1}{2}}=\\frac{1}{\\sqrt{x}}$$"
],
"result": "=6\\cdot\\:\\frac{1}{2}\\cdot\\:\\frac{1}{\\sqrt{x}}y^{2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}\\cdot\\frac{d}{e}=\\frac{a\\:\\cdot\\:b\\:\\cdot\\:d}{c\\:\\cdot\\:e}$$",
"result": "=\\frac{1\\cdot\\:1\\cdot\\:6y^{2}}{2\\sqrt{x}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:1\\cdot\\:6=6$$",
"result": "=\\frac{6y^{2}}{2\\sqrt{x}}"
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{6}{2}=3$$",
"result": "=\\frac{3y^{2}}{\\sqrt{x}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s73h3lYgcjAIniPCqwG08uuEQ2tnn4MvCupPKnOdfx5iu2oVwn9rqBac7JV/bk/6m+q47vuWedXv2WUg94ER8IwcsvPm+oG99EJykovdJnkIl/CGrjd5Qc8wJrT39a5pl372wZm7kDUxdE6YSmfEbr2mN2QVk5Uy6JLEPS3CeYJ2GtV4LZMo8tVPAr16ZyS6QXv6jY2qcQmwXzGCGE7nZw2E5OQF0x1Pgvk6xils6k/ew="
}
}
],
"meta": {
"solvingClass": "Derivatives",
"practiceLink": "/practice/derivatives-practice#area=main&subtopic=Partial%20Derivatives",
"practiceTopic": "Partial Derivatives"
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Treat as a constant
Take the constant out:
Apply radical rule:
Apply the Power Rule:
Simplify
Popular Examples
(xsqrt(x))^'(dy)/(dt)+7y=e^{4t},y(0)=10(\partial)/(\partial x)(e^{-ax^2})(x+4)^2y^'+3(x+4)y=4integral of (50)/((x-1)(x^2+49))
Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(6y^2sqrt(x)) ?
The answer to (\partial)/(\partial x)(6y^2sqrt(x)) is (3y^2)/(sqrt(x))