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Popular >

derivative of sqrt(8+\sqrt{4x)}

Solution

\frac{d}{d x} (8 + 4 x)

Solution

\frac{1}{2 x 8 + 2 x}

Solution steps

\frac{d}{d x} (8 + 4 x)

Apply the chain rule:

\frac{1}{2 8 + 4 x} \frac{d}{d x} (8 + 4 x)

= \frac{1}{2 8 + 4 x} \frac{d}{d x} (8 + 4 x)

\frac{d}{d x} (8 + 4 x) = \frac{1}{x}

= \frac{1}{2 8 + 4 x} \cdot \frac{1}{x}

Simplify

\frac{1}{2 8 + 4 x} \cdot \frac{1}{x} : \frac{1}{2 x 8 + 2 x}

= \frac{1}{2 x 8 + 2 x}

Popular Examples

integral of sqrt(x\sqrt{x\sqrt{x)}}

\int x x x d x

tangent of f(x)=8(x-1/x)^3,\at x=2 tangent of

f (x) = 8 (x - \frac{1}{x})^{3}, at x = 2

sum from n=0 to infinity of (3x)^n

n = 0 \sum \infty (3 x)^{n}

tangent of y=cot(x),\at x= pi/4 tangent of

y = cot (x), at x = \frac{π}{4}

derivative of sin(ax^2)

\frac{d}{d x} (sin (a x^{2}))

Frequently Asked Questions (FAQ)

What is the derivative of sqrt(8+\sqrt{4x)} ?
The derivative of sqrt(8+\sqrt{4x)} is 1/(2sqrt(x)\sqrt{8+2\sqrt{x)}}
What is the first derivative of sqrt(8+\sqrt{4x)} ?
The first derivative of sqrt(8+\sqrt{4x)} is 1/(2sqrt(x)\sqrt{8+2\sqrt{x)}}