What is the tangent of y=cot(x),\at x= pi/4 ?

The tangent of y=cot(x),\at x= pi/4 is y=-2x+1+pi/2

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tangent of y=cot(x),\at x= pi/4

tangent of

y = cot (x), at x = \frac{π}{4}

y = - 2 x + 1 + \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 1)

Find the slope of

y = cot (x) : \frac{d y}{d x} = - csc^{2} (x)

Compute the slope of

y = cot (x)

x = \frac{π}{4} : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{π}{4}, 1) : y = - 2 x + 1 + \frac{π}{2}

y = - 2 x + 1 + \frac{π}{2}

\frac{d}{d x} (sin (a x^{2}))

\int t^{3} + 1 d t

\int_{6}^{8} \frac{88}{( x - 6 ) ^{3}} d x

\int x (x - 1)^{7} d x

\int e + sec^{2} (θ) - e^{θ} d θ

What is the tangent of y=cot(x),\at x= pi/4 ?
The tangent of y=cot(x),\at x= pi/4 is y=-2x+1+pi/2