What is the first derivative of xy^3 ?

The first derivative of xy^3 is y^3

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derivative of xy^3

derivative of

x y^{3}

y^{3}

Solution steps

\frac{d}{d x} (x y^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{3} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= y^{3} \cdot 1

Simplify

= y^{3}

\frac{d y}{d x}, y = x + \frac{1}{x}

\frac{d}{d x} (\frac{3 x ^{2} - 1}{2 x + 5})

n = 0 \sum \infty 6 (\frac{4}{5})^{n}

\int \frac{tan ( ln ( 4 x + 2 ) )}{4 x + 2} d x

(5 x + 3) x^{2}