What is the sum from n=0 to infinity of 6(4/5)^n ?

The sum from n=0 to infinity of 6(4/5)^n is 30

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sum from n=0 to infinity of 6(4/5)^n

n = 0 \sum \infty 6 (\frac{4}{5})^{n}

30

Solution steps

n = 0 \sum \infty 6 (\frac{4}{5})^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 6 \cdot n = 0 \sum \infty (\frac{4}{5})^{n}

Apply Series Geometric Test:

5

= 6 \cdot 5

Simplify

= 30

\int \frac{tan ( ln ( 4 x + 2 ) )}{4 x + 2} d x

(5 x + 3) x^{2}

n = 0 \sum \infty (\frac{2}{3}) (\frac{5}{4})^{n}

e^{- 2 s} \frac{1}{( s + 1 ) ^{2}}

y^{^{'}} = \frac{x ^{2}}{y}

What is the sum from n=0 to infinity of 6(4/5)^n ?
The sum from n=0 to infinity of 6(4/5)^n is 30