What is implicit (dy)/(dx),y=x+1/x ?

The answer to implicit (dy)/(dx),y=x+1/x is (dy)/(dx)=1-1/(x^2)

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implicit (dy)/(dx),y=x+1/x

implicit derivative

\frac{d y}{d x}, y = x + \frac{1}{x}

\frac{d y}{d x} = 1 - \frac{1}{x ^{2}}

Solution steps

y = x + \frac{1}{x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = 1 - \frac{1}{x ^{2}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 1 - \frac{1}{x ^{2}}

\frac{d y}{d x} = 1 - \frac{1}{x ^{2}}

\frac{d}{d x} (\frac{3 x ^{2} - 1}{2 x + 5})

n = 0 \sum \infty 6 (\frac{4}{5})^{n}

\int \frac{tan ( ln ( 4 x + 2 ) )}{4 x + 2} d x

(5 x + 3) x^{2}

n = 0 \sum \infty (\frac{2}{3}) (\frac{5}{4})^{n}

What is implicit (dy)/(dx),y=x+1/x ?
The answer to implicit (dy)/(dx),y=x+1/x is (dy)/(dx)=1-1/(x^2)