What is the derivative of (2x^3+4(x^4-4x)) ?

The derivative of (2x^3+4(x^4-4x)) is 14x^6-16x^3-16

What is the first derivative of (2x^3+4(x^4-4x)) ?

The first derivative of (2x^3+4(x^4-4x)) is 14x^6-16x^3-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((2 x^{3} + 4) (x^{4} - 4 x))

14 x^{6} - 16 x^{3} - 16

Solution steps

\frac{d}{d x} ((2 x^{3} + 4) (x^{4} - 4 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2 x^{3} + 4, g = x^{4} - 4 x

= \frac{d}{d x} (2 x^{3} + 4) (x^{4} - 4 x) + \frac{d}{d x} (x^{4} - 4 x) (2 x^{3} + 4)

\frac{d}{d x} (2 x^{3} + 4) = 6 x^{2}

\frac{d}{d x} (x^{4} - 4 x) = 4 x^{3} - 4

= 6 x^{2} (x^{4} - 4 x) + (4 x^{3} - 4) (2 x^{3} + 4)

Simplify

6 x^{2} (x^{4} - 4 x) + (4 x^{3} - 4) (2 x^{3} + 4) : 14 x^{6} - 16 x^{3} - 16

= 14 x^{6} - 16 x^{3} - 16

\int_{0}^{1} \frac{5}{1 - x ^{2}} d x

y = (x + 5) (x^{3} - 1) (x^{2} - x + 3)

\frac{d}{d x} (2 e^{7 x})

\int \frac{1}{5 - 4 sin ( x ) + 3 cos ( x )} d x

- 4 y^{^{'}} + y = 1

What is the derivative of (2x^3+4(x^4-4x)) ?
The derivative of (2x^3+4(x^4-4x)) is 14x^6-16x^3-16
What is the first derivative of (2x^3+4(x^4-4x)) ?
The first derivative of (2x^3+4(x^4-4x)) is 14x^6-16x^3-16