What is the integral from 0 to 1 of 5/(sqrt(1-x^2)) ?

The integral from 0 to 1 of 5/(sqrt(1-x^2)) is (5pi)/2

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integral from 0 to 1 of 5/(sqrt(1-x^2))

\int_{0}^{1} \frac{5}{1 - x ^{2}} d x

\frac{5 π}{2}

Decimal Notation

7.85398 \dots

Solution steps

\int_{0}^{1} \frac{5}{1 - x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int_{0}^{1} \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= 5 [arcsin (x)]_{0}^{1}

Compute the boundaries:

\frac{π}{2}

= 5 \cdot \frac{π}{2}

Simplify

= \frac{5 π}{2}

y = (x + 5) (x^{3} - 1) (x^{2} - x + 3)

\frac{d}{d x} (2 e^{7 x})

\int \frac{1}{5 - 4 sin ( x ) + 3 cos ( x )} d x

- 4 y^{^{'}} + y = 1

e^{x}, - x + 1, x = 1

What is the integral from 0 to 1 of 5/(sqrt(1-x^2)) ?
The integral from 0 to 1 of 5/(sqrt(1-x^2)) is (5pi)/2